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## How many molecules are in a mole of Cl2?

39.2 g Cl2(1 mole of Cl270.9 g Cl2)(6.022⋅1023molecules Cl21 mole Cl2)=**3.33⋅1023 molecules Cl2** . Hence, the answer is 3.33⋅1023 molecules of Cl2. Note that 6.022⋅1023 is also known as Avogadro’s number, and it can be referred to as the number of molecules in one mole of that substance.

## How do you find the number of molecules in a mole?

**Converting between molecules and moles is done by either multiplying by or dividing by Avogadro’s number:**

- To go from moles to molecules, multiply the number of moles by 6.02 x 10
^{23}. - To go from molecules to moles, divide the numbers of molecules by 6.02 x 10
^{23}.

## How many atoms are present in 1g of Cl2?

1g of Cl2 has **1.67 x 10²² atoms**.

## How many molecules are there in 15.7 liters of chlorine gas?

And it is a fact that STP , 1 mole of an ideal gas has a volume of 22.414⋅L . So we take the quotient, 15.7⋅L22.414⋅L⋅mol−1 to get a molar quantity, and multiply this amount by Avogadro’s number to get the number of molecules. 15.7⋅L 22.414⋅L ⋅mol−1 × 6.022×1023⋅mol−1 = ??

## How many moles are in 1g of Cl2?

1 grams Cl2 is equal to **0.014103178856514 mole**.

## How many chlorine atoms are there in 1 mole of chlorine molecules?

One mole of chlorine weighs 70 grams. Just like a dozen equals twelve, a mole equals Avogadro’s number of atoms or **6.02 × 10 ^{23}**.

## How many Cl2 molecules are there in 10 moles of chlorine gas?

If you have a mole of cl2, then you have **6.02 * 10^23 molecules** of cl2. If you want to calculate for atoms however, you can see that each molecule has two atoms of cl. Therefore you have 2* 6.02 * 10^23 chlorine atoms.