**Contents**show

## How many moles is 80 grams?

The question says that we need to calculate the moles in 80g of sulfur. So the number of moles present in 80grams of sulfur is **0.3125 moles**.

## How many atoms are in 80 g of oxygen?

1 mol contains avogadro no. of atom i.e., **6.02×1023 atoms**.

## How many moles are in 100g of oxygen?

There are **6.25 moles** of oxygen in 100g of Water.

## How many number of gram atoms are present in 80 g of calcium?

where, $n$ is the number of moles of calcium, $W$ is the weight of calcium and $M$ is the molar mass of calcium. Therefore, the number of moles present in $80g$ of calcium is **$2**,mol$ . $1,mole=6.022times {{10}^{23}}$ particles. This number is known as Avogadro’s number $({{N}_{A}})$.

## Which of the following is correct for 1 mole methane?

One mole of methane specifies **NA , Avogadro’s number of methane** molecules, i.e. 6.022×1023 individual CH4 molecules. And thus it contains 4×6.022×1023 hydrogen atoms .

## How many moles are in 32g of oxygen?

And we know that When the given mass is divided by the molar mass of the gas. We will get the number of moles present in that gas so here it is =**1**. we get the answer as 1. So the number of moles present in 32 gram of oxygen is 1.

## What is the number of moles in 0.025 g NH4 2Cr2O7?

Here are all the answers:

Description | Match: |
---|---|

How many MOLES in 0.025 g (NH4)2Cr2O7? | 9.91 X 10^-5 or 0.000099 mol |

Mr. Adamek’s First Name | What is Dustin? |

The percent composition of Barium in BaCrO4 | What is 54.21%? |

The lowest whole-number ratio of the elements in a compound | What is empirical formula? |

## Which statement is correct for 1 mole of O2?

Solution — 1 molecule of O2 **= 2 oxygen atoms** So, 1 mole of O2 = 2 mole oxygen atoms = 2 × 6.022 × 1023 = 12.044 ×1023 oxygen atoms. Question 4.