**Contents**show

## How many grams of potassium chlorate should be decomposed completely?

Complete answer:

-Therefore, **24.4 grams** of potassium chlorate should be decomposed to obtain 9.6 grams of oxygen.

## How many moles are in KClO3?

According to the equation **2 moles** of KClO3 gives 3 moles of oxygen (O2). To obtain 6 moles of oxygen we multiply chemical equation by 2. Hence, 4 moles of KClO3 are required to give 6 moles of oxygen.

## How many moles of oxygen are produced when 3.0 moles of potassium chlorate decompose completely?

(3/2)*(3.0) moles O_{2}, or **4.5 moles** of O_{2}.

## How many moles of KClO3 are required to produce 2.4 moles O2?

Therefore **1.6 moles** of KClO_{3} are required to produce 2.4 moles of O_{2}.

## How many moles of electrons weigh 1kg?

Or, 1 kg will contain = $dfrac{1}{{9.108 times 6.022}} times {**10^8}$ moles** of electrons. Thus, $dfrac{1}{{9.108 times 6.022}} times {10^8}$ moles of electrons will weigh one kilogram. So, the correct answer is “Option D”.

## What is the decomposition of potassium chlorate?

Consider the title reaction, the thermal decomposition of potassium chlorate. When KClO3 is heated strongly, it breaks down, **releasing oxygen gas and leaving behind** a thermally stable (i.e., heat-insensitive) solid residue of an ionic potassium compound.

## How many moles of oxygen are produced when 2 mol of potassium chlorate KCLO3 decompose quizlet?

Two moles of potassium chloride (KCl) and **three moles of oxygen (O2)** are produced from the decomposition of two moles of potassium chlorate (KClO3). You just studied 11 terms!

## How many moles of oxygen are produced by the decomposition of eight moles of potassium chlorate?

Therefore, to produce 8 moles of oxygen, 2×83=**5.33 moles** of potassium chlorate is needed.

## How many moles of potassium chlorate KClO3 are needed to produce 15 moles?

You’d need **33.3 moles** of potassium chlorate, KClO3 , to produce that much oxygen.

## How many moles of oxygen can be obtained by the decomposition?

The correct answer of this question is **5 moles** of oxygen gas can be produced during the electrolytic decomposition of 180 g of water.