Your question: How many moles of potassium chlorate should be decompose completely?

How many grams of potassium chlorate should be decomposed completely?

Complete answer:

-Therefore, 24.4 grams of potassium chlorate should be decomposed to obtain 9.6 grams of oxygen.

How many moles are in KClO3?

​According to the equation 2 moles of KClO3 gives 3 moles of oxygen (O2). To obtain 6 moles of oxygen we multiply chemical equation by 2. Hence, 4 moles of KClO3 are required to give 6 moles of oxygen.

How many moles of oxygen are produced when 3.0 moles of potassium chlorate decompose completely?

(3/2)*(3.0) moles O2, or 4.5 moles of O2.

How many moles of KClO3 are required to produce 2.4 moles O2?

Therefore 1.6 moles of KClO3 are required to produce 2.4 moles of O2.

How many moles of electrons weigh 1kg?

Or, 1 kg will contain = $dfrac{1}{{9.108 times 6.022}} times {10^8}$ moles of electrons. Thus, $dfrac{1}{{9.108 times 6.022}} times {10^8}$ moles of electrons will weigh one kilogram. So, the correct answer is “Option D”.

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What is the decomposition of potassium chlorate?

Consider the title reaction, the thermal decomposition of potassium chlorate. When KClO3 is heated strongly, it breaks down, releasing oxygen gas and leaving behind a thermally stable (i.e., heat-insensitive) solid residue of an ionic potassium compound.

How many moles of oxygen are produced when 2 mol of potassium chlorate KCLO3 decompose quizlet?

Two moles of potassium chloride (KCl) and three moles of oxygen (O2) are produced from the decomposition of two moles of potassium chlorate (KClO3). You just studied 11 terms!

How many moles of oxygen are produced by the decomposition of eight moles of potassium chlorate?

Therefore, to produce 8 moles of oxygen, 2×83=5.33 moles of potassium chlorate is needed.

How many moles of potassium chlorate KClO3 are needed to produce 15 moles?

You’d need 33.3 moles of potassium chlorate, KClO3 , to produce that much oxygen.

How many moles of oxygen can be obtained by the decomposition?

The correct answer of this question is 5 moles of oxygen gas can be produced during the electrolytic decomposition of 180 g of water.