What is the volume occupied by 1 mole of liquid water?
Explanation: One mole of liquid water is equal to to 18 grams of water. According to the density of water at normal temperature pressure the value 1gram per centimetre cube. hence the volume which is occupied by 18 grams of water will be equal to 18 cm ³ or 18 ml.
What is volume of 1 molecule of water?
Volume of 1 molecule of water = 2.989 × 10–23 ≈ 3 × 10–23.
How do you find molar volume of water?
At standard Temperature and Pressure (STP) the molar volume (Vm) is the volume occupied by one mole of a chemical element or a chemical compound. It can be calculated by dividing the molar mass (M) by mass density (ρ).
Can you use Torr in PV nRT?
In Ideal Gas Law, there’s gas constant R that we need to use in the formula PV=nRT. There are times when we are given different units and we need to do conversioins and here are the proper units we use. Since PV= nRT, … For pressure we use units like atm, kPa and mmHg (torr).
How many liters are in 1 mole of H2O?
For water, 1 mole = 18 g= 22.4 liter.
How do you calculate the volume of liquid water?
Pour the liquid into the container and record the weight of the container plus the liquid. Subtract the weight of the container to get the weight of the liquid. Look up or calculate the density of the liquid, then determine the volume of the liquid by dividing the mass of the liquid by the density.
What is the volume occupied by 1 mole of water vapor at STP?
At Standard Temperature and Pressure (STP), 1 mole of any gas will occupy a volume of 22.4 L.